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Price rounding: identical labels, different wave checks

Two values displayed as 110.00 can lie on opposite sides of a wave boundary. Check retained prices rather than the number of printed decimals.

Student Wyckoff editorial team

Published: (UTC+3)

A chart label may show fewer decimals than the underlying price. Identical labels therefore need not mean identical values. In this invented exercise, rounding to two decimals hides a difference that changes one price check for an ordinary upward impulse.

Separate the retained price from its display

Check only the relationship between waves 1 and 4: in the selected ordinary upward model, wave 4’s low must remain above the end of wave 1. In A and B, that first-wave endpoint is 110.0041. Four decimal places are supplied for this exercise; no claim is made about a real instrument’s precision. Every displayed value is rounded to two decimals.

Compare three records of one check

A and B differ only in the proposed fourth-wave low. C retains only the labels 110.00 and 110.00, with no original values. The table examines one boundary relationship, not a complete bar sequence or a validated pattern. Equal labels cannot tell A from B.

Invented prices: A and B retain originals; C keeps only rounded labels
CaseOriginal end of 1Original low of 4Exact differenceDisplay: end 1 / low 4Result of this check
A110.0041110.0042+0.0001110.00 / 110.00Above boundary: this check passes
B110.0041110.0040−0.0001110.00 / 110.00Below boundary: ordinary hypothesis rejected
C???110.00 / 110.00Original values unavailable

Subtract before rounding

For A,110.0042 −110.0041 = +0.0001: the low is above the selected boundary, so this check passes. For B,110.0040 −110.0041 = −0.0001: the low enters wave 1 territory and rejects this ordinary impulse hypothesis. Subtracting displayed 110.00 −110.00 instead removes the distinction. In C, the exact difference cannot be established.

Ask whether lost digits can be recovered

If only a rounded copy remains, printing more trailing zeros does not recreate the original digits. Do not guess a convenient value or introduce an arbitrary tolerance to rescue a count. Retrieve the retained source and identify the specific bars and their extremes. If that precision cannot be obtained, leave this check unresolved.

C displays 110.00 and 110.00. Does formatting them as 110.000000 reveal the original price difference?

No. The presentation of the stored values changed, not their information content. The originals could have been A, B or other values with the same rounded labels. Retrieve source values with known precision. Until then, this boundary comparison remains unresolved.

Keep the source and the limits of the conclusion

Keep the original export separate from reading tables. Record instrument, source, interval, selected bars and display rounding, then compare the same underlying quantities. Even A does not establish a complete impulse: context and subdivisions are still required. Obtain real-market precision information from the relevant provider. The CSV and first-calculation guides support a repeatable review; this exercise describes no internal numerical behavior of the application.

First calculation → · Compare Pro and Light → · Request Pro →

Points, ticks and money are different quantities

Assume a fictional linear specification: tick size 0.25 points, point value 50 per unit and quantity 2.100→100.75 is 0.75 points or 3 ticks. One tick is worth 0.25×50=12.5 per unit; conditional gross result is 3×12.5×2=75 before costs.

This is no real contract specification. Obtain tick size and multiplier for the actual instrument, date and currency. Two displayed decimals do not determine tick size; “tick” can also mean an individual trade record. Preserve adjustments and rounding separately. Execution is not established, and 75 is not net profit.

Points, ticks and money are different quantitiesThree 0.25 steps equal 0.75 points;12.5 per tick per unit and quantity 2 give conditional gross 75.Price / points9999.688100.38101.06101.7501233×0.25 = 0.75; 0.75×50×2 = 75
Three 0.25 steps equal 0.75 points;12.5 per tick per unit and quantity 2 give conditional gross 75.
QuantityCalculation / value
ΔP100.75−100=0.75
tick0.25
n_ticks0.75/0.25=3
V_point50
V_tick0.25×50=12.5
q2
gross3×12.5×2=75

Does displaying 100.10 prove an allowed step 0.01?

No. Formatting is not an exchange grid. Under our chosen 0.25 grid from 100, that level is not a permitted original increment.

Sources and limits

Prices and arithmetic are original teaching material. The ordinary impulse rule and the use of actual extremes come from the existing lessons; retaining the original export is documented in the CSV guide. No real quotations, exchange tick size or tested trading strategy is presented.