Student Wyckoff · Elliott Wave

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Price levels, breakouts and retests in an Elliott wave hypothesis

Support and resistance zones, a closing breakout rule, failed breakouts and retests in separate invented cases.

Student Wyckoff editorial team

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A price level describes an observation area; a wave count proposes movement structure. Separate fictional cases show what is already observable and which conclusions still require evidence.

Freeze the zones first

Support names an area considered for a slowing decline or possible bounce; resistance names an area considered for a pause in an advance. These are testable interpretations, not walls that must hold. In this exercise, reference prices 110/109.9 and 100/100.1 are selected beforehand, then R=[109.8,110.2] and S=[99.8,100.2] are fixed. Each width 0.4 is our example convention, not a universal tolerance.

Save the source, interval, completed-bar cutoff and zone-selection time before the next observation. Record the proposed wave role and its structural invalidation separately: a zone edge is not automatically a wave boundary. A possible change from resistance to support remains a hypothesis to examine rather than a promised bounce.

Invented preselected R109.8–110.2 and S99.8–100.2, from reference prices 110/109.9 and 100/100.1. Width 0.4 is not a market-precision estimate.98101.5105108.5112100110100.1109.901234R:[109.8,110.2]; S:[99.8,100.2]
Invented preselected R109.8–110.2 and S99.8–100.2, from reference prices 110/109.9 and 100/100.1. Width 0.4 is not a market-precision estimate.
ItemCalculation or value
R[109.8,110.2]
S[99.8,100.2]
P_R110 /109.9
P_S100 /100.1

Does touching S establish the end of wave two?

No. It establishes only price relative to the selected zone. Internal structure and the condition for that particular second-wave hypothesis need separate checks.

Choose an exact breakout condition

For a separate experiment, require a completed close C>110.2. Bar 5 with O109.6,H111,L109.3,C110.6 meets it. High 111 alone without the required close would not pass; C=110.2 is not greater than 110.2 either. This is our event-recording rule, not a mandatory breakout definition for every market.

The condition becomes available after bar 5 finishes. It does not establish a purchase, an available fill price or a confirmed third wave. Keep separate observation, wave-hypothesis and possible execution records. A different interval or rule is a separate experiment; subsequent direction remains unknown at this cutoff.

Separate invented bar 5: O109.6 H111 L109.3 C110.6. Its completed close exceeds the fixed upper edge 110.2 of R.108.8109.45110.1110.75111.45C5=110.6 > 110.2
Separate invented bar 5: O109.6 H111 L109.3 C110.6. Its completed close exceeds the fixed upper edge 110.2 of R.
ItemCalculation or value
O/H/L/C109.6/111/109.3/110.6
RuleC>110.2
C5110.6>110.2

Bar 5 passes. Can a filled purchase be recorded?

No. Close 110.6 establishes only C>110.2. The example supplies no submitted order, execution price or fill evidence.

A failed breakout needs a later test

In another independent case, bar 5 closes 110.6. Beforehand, define a return as a completed close below 109.8 within the next two completed bars. Bar 6 gives C109.6<109.8, satisfying that return test on the first of the two bars. Its other OHLC values are not supplied.

Here, “false breakout” refers to this finite test, not a universal shape or future knowledge at bar 5. Distinguish it from a wick outside the zone without an initial qualifying close. Preserve the original event and later return rather than widening the zone after the outcome. Neither the return nor its name determines a unique alternative Elliott count.

Independent closing-price case: bar 5 C110.6, bar 6 C109.6; the chosen horizon is two subsequent bars and the return threshold is below 109.8.109109.6110.3110.9111.5C5:110.6C6:109.645678C6 < 109.8; Δt=1 ≤ 2
Independent closing-price case: bar 5 C110.6, bar 6 C109.6; the chosen horizon is two subsequent bars and the return threshold is below 109.8.
ItemCalculation or value
C5110.6>110.2
C6109.6<109.8
Δt1≤2

Was bar 6’s result knowable at bar 5’s close?

No. Bar 5 supplied the recorded breakout condition. The return test became available only after bar 6 completed.

A retest is a separate post-break observation

In a third independent case, bar 5 closes 110.6 and bar 6 is O110.7,H110.9,L110.1,C110.4. Low 110.1 enters R109.8–110.2 while close 110.4 stays above 110.2. Under this chosen convention, that is an observed retest from above, distinct from a close below 109.8.

Former resistance is now being examined as possible support. Future price is still unknown: the touch and close guarantee neither continuation, reversal nor wave completion. If a later confirming bar is required, define its condition beforehand and do not include it among facts already available. Execution remains a separate question.

Independent retest: after C110.6, bar 6 O110.7 H110.9 L110.1 C110.4. Its low is inside R and its close above R; no continuation is shown.109109.6110.2110.8111.456L6=110.1; C6=110.4 > 110.2
Independent retest: after C110.6, bar 6 O110.7 H110.9 L110.1 C110.4. Its low is inside R and its close above R; no continuation is shown.
ItemCalculation or value
O/H/L/C110.7/110.9/110.1/110.4
L6109.8≤110.1≤110.2
C6110.4>110.2

Does the bar 6 retest guarantee a rising next bar?

No. The zone touch and close 110.4 are known. A subsequent bar is not yet supplied.

HH/HL and wave structure answer different questions

Consider separate invented turns 100→110→104→113→107→115. Highs 110,113,115 rise and lows 100,104,107 also rise: HH/HL describes the selected swing scale. The swing-selection rule and observation-availability times need their own record; outer points do not reveal internal waves.

Assigning 0–5 of an ordinary upward impulse to those same points makes proposed 4=107 overlap wave 1 territory ending 110. That impulse hypothesis fails while the observed HH/HL description remains. Renaming it a diagonal is not an automatic repair. The adjacent Dow/Elliott article develops the comparison.

Independent teaching turns 100,110,104,113,107,115 retain HH/HL, but assigning 0–5 violates ordinary-impulse non-overlap.97102.3107.5112.81180:1001?:1102?:1043?:1134:1075?:115012345107 < 110
Independent teaching turns 100,110,104,113,107,115 retain HH/HL, but assigning 0–5 violates ordinary-impulse non-overlap.
ItemCalculation or value
HH110<113<115
HL104<107
4 / 1107<110

Do rising highs and lows validate this ordinary impulse?

No. They describe the swings, but 4=107 overlaps 1. Another model requires its own evidence.

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